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531255543113 = 3181167008973
BaseRepresentation
bin1111011101100010100…
…11000100010101001001
31212210021010000210222102
413232301103010111021
532201002404334423
61044015550003145
753245002415631
oct7566123042511
91783233023872
10531255543113
111953389a4669
1286b644a64b5
133b135683799
141b9da2d96c1
15dc44ab9c28
hex7bb14c4549

531255543113 has 4 divisors (see below), whose sum is σ = 531422555268. Its totient is φ = 531088530960.

The previous prime is 531255543097. The next prime is 531255543131. The reversal of 531255543113 is 311345552135.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 101014001929 + 430241541184 = 317827^2 + 655928^2 .

It is a cyclic number.

It is not a de Polignac number, because 531255543113 - 24 = 531255543097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (531255543713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 83501306 + ... + 83507667.

It is an arithmetic number, because the mean of its divisors is an integer number (132855638817).

Almost surely, 2531255543113 is an apocalyptic number.

It is an amenable number.

531255543113 is a deficient number, since it is larger than the sum of its proper divisors (167012155).

531255543113 is a wasteful number, since it uses less digits than its factorization.

531255543113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 167012154.

The product of its digits is 135000, while the sum is 38.

The spelling of 531255543113 in words is "five hundred thirty-one billion, two hundred fifty-five million, five hundred forty-three thousand, one hundred thirteen".

Divisors: 1 3181 167008973 531255543113