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531300111 = 31371292701
BaseRepresentation
bin11111101010101…
…111111100001111
31101000201211201220
4133222233330033
52042003100421
6124415334423
716110655626
oct3752577417
91330654656
10531300111
112529a5701
12129b21413
13860c3a84
14507c26bd
153199c3c6
hex1faaff0f

531300111 has 8 divisors (see below), whose sum is σ = 713571504. Its totient is φ = 351614400.

The previous prime is 531300101. The next prime is 531300149. The reversal of 531300111 is 111003135.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 531300111 - 29 = 531299599 is a prime.

It is a super-2 number, since 2×5313001112 = 564559615897224642, which contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (531300101) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 645940 + ... + 646761.

It is an arithmetic number, because the mean of its divisors is an integer number (89196438).

Almost surely, 2531300111 is an apocalyptic number.

531300111 is a deficient number, since it is larger than the sum of its proper divisors (182271393).

531300111 is a wasteful number, since it uses less digits than its factorization.

531300111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1292841.

The product of its (nonzero) digits is 45, while the sum is 15.

The square root of 531300111 is about 23049.9481778159. The cubic root of 531300111 is about 809.9284146461.

Adding to 531300111 its reverse (111003135), we get a palindrome (642303246).

The spelling of 531300111 in words is "five hundred thirty-one million, three hundred thousand, one hundred eleven".

Divisors: 1 3 137 411 1292701 3878103 177100037 531300111