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53130013 = 163325951
BaseRepresentation
bin1100101010101…
…1001100011101
310200222021200021
43022223030131
5102100130023
65134432141
71213411666
oct312531435
9120867607
1053130013
1127a99402
1215962651
13b012ca1
1470b036d
1549e735d
hex32ab31d

53130013 has 4 divisors (see below), whose sum is σ = 53456128. Its totient is φ = 52803900.

The previous prime is 53129971. The next prime is 53130019. The reversal of 53130013 is 31003135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31003135 = 56200627.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53130013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53130019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 162813 + ... + 163138.

It is an arithmetic number, because the mean of its divisors is an integer number (13364032).

Almost surely, 253130013 is an apocalyptic number.

It is an amenable number.

53130013 is a deficient number, since it is larger than the sum of its proper divisors (326115).

53130013 is a wasteful number, since it uses less digits than its factorization.

53130013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 326114.

The product of its (nonzero) digits is 135, while the sum is 16.

The square root of 53130013 is about 7289.0337494074. The cubic root of 53130013 is about 375.9354730260.

Adding to 53130013 its reverse (31003135), we get a palindrome (84133148).

The spelling of 53130013 in words is "fifty-three million, one hundred thirty thousand, thirteen".

Divisors: 1 163 325951 53130013