Base | Representation |
---|---|
bin | 111100011001110000001100… |
… | …1000101101101001001000000 |
3 | 2120200012021012211002020022022 |
4 | 1320303200121011231021000 |
5 | 1024114400223124413100 |
6 | 5121554101201301012 |
7 | 216624344364556010 |
oct | 17063403105551100 |
9 | 2520167184066268 |
10 | 531305055310400 |
11 | 1443212326a0598 |
12 | 4b70a590034768 |
13 | 19a5cb0c3534a7 |
14 | 952b43252dc40 |
15 | 41656e532be85 |
hex | 1e3381916d240 |
531305055310400 has 168 divisors, whose sum is σ = 1507813111611840. Its totient is φ = 180490524272640.
The previous prime is 531305055310261. The next prime is 531305055310411. The reversal of 531305055310400 is 4013550503135.
It is a super-3 number, since 3×5313050553104003 (a number of 45 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 216384482 + ... + 218826081.
Almost surely, 2531305055310400 is an apocalyptic number.
531305055310400 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
531305055310400 is an abundant number, since it is smaller than the sum of its proper divisors (976508056301440).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
531305055310400 is a wasteful number, since it uses less digits than its factorization.
531305055310400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 435210701 (or 435210686 counting only the distinct ones).
The product of its (nonzero) digits is 67500, while the sum is 35.
The spelling of 531305055310400 in words is "five hundred thirty-one trillion, three hundred five billion, fifty-five million, three hundred ten thousand, four hundred".
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