Base | Representation |
---|---|
bin | 111100011001110011111110… |
… | …0001111101001101101101111 |
3 | 2120200020001010201221211121211 |
4 | 1320303213330033221231233 |
5 | 1024120013323244010020 |
6 | 5122001521405135251 |
7 | 216625052303502025 |
oct | 17063477417515557 |
9 | 2520201121854554 |
10 | 531313161313135 |
11 | 14432471228a403 |
12 | 4b71007285a527 |
13 | 19a6080182c406 |
14 | 952b9a0d0c715 |
15 | 4165a1bcb585a |
hex | 1e339fc3e9b6f |
531313161313135 has 16 divisors (see below), whose sum is σ = 643898778321600. Its totient is φ = 420835341222400.
The previous prime is 531313161313111. The next prime is 531313161313139.
531313161313135 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 531313161313135 - 27 = 531313161313007 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (531313161313139) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23096391 + ... + 39950839.
It is an arithmetic number, because the mean of its divisors is an integer number (40243673645100).
Almost surely, 2531313161313135 is an apocalyptic number.
531313161313135 is a deficient number, since it is larger than the sum of its proper divisors (112585617008465).
531313161313135 is a wasteful number, since it uses less digits than its factorization.
531313161313135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16916978.
The product of its digits is 109350, while the sum is 40.
The spelling of 531313161313135 in words is "five hundred thirty-one trillion, three hundred thirteen billion, one hundred sixty-one million, three hundred thirteen thousand, one hundred thirty-five".
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