531314440231 has 4 divisors (see below), whose sum is σ = 531323556264. Its totient is φ = 531305324200.

The previous prime is 531314440229. The next prime is 531314440243. The reversal of 531314440231 is 132044413135.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 531314440231 - 2¹ = 531314440229 is a prime.

It is a super-2 number, since 2×531314440231² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 531314440193 and 531314440202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (531314440201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4470025 + ... + 4587346.

It is an arithmetic number, because the mean of its divisors is an integer number (132830889066).

Almost surely, 2^531314440231 is an apocalyptic number.

531314440231 is a deficient number, since it is larger than the sum of its proper divisors (9116033).

531314440231 is an equidigital number, since it uses as much as digits as its factorization.

531314440231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9116032.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 531314440231 its reverse (132044413135), we get a palindrome (663358853366).

The spelling of 531314440231 in words is "five hundred thirty-one billion, three hundred fourteen million, four hundred forty thousand, two hundred thirty-one".