Search a number
-
+
53131540299 = 317710513433
BaseRepresentation
bin110001011110111000…
…101111011101001011
312002010211100220022220
4301132320233131023
51332303133242144
640224105145123
73560435432565
oct613670573513
9162124326286
1053131540299
1120595407692
12a36978b1a3
13501978bb56
1428005b8335
1515ae76d919
hexc5ee2f74b

53131540299 has 4 divisors (see below), whose sum is σ = 70842053736. Its totient is φ = 35421026864.

The previous prime is 53131540271. The next prime is 53131540337. The reversal of 53131540299 is 99204513135.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53131540299 - 27 = 53131540171 is a prime.

It is a super-2 number, since 2×531315402992 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 53131540299.

It is not an unprimeable number, because it can be changed into a prime (53131548299) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8855256714 + ... + 8855256719.

It is an arithmetic number, because the mean of its divisors is an integer number (17710513434).

Almost surely, 253131540299 is an apocalyptic number.

53131540299 is a deficient number, since it is larger than the sum of its proper divisors (17710513437).

53131540299 is a wasteful number, since it uses less digits than its factorization.

53131540299 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17710513436.

The product of its (nonzero) digits is 145800, while the sum is 42.

The spelling of 53131540299 in words is "fifty-three billion, one hundred thirty-one million, five hundred forty thousand, two hundred ninety-nine".

Divisors: 1 3 17710513433 53131540299