Base | Representation |
---|---|
bin | 110001011110111000… |
… | …101111011101001100 |
3 | 12002010211100220022221 |
4 | 301132320233131030 |
5 | 1332303133242200 |
6 | 40224105145124 |
7 | 3560435432566 |
oct | 613670573514 |
9 | 162124326287 |
10 | 53131540300 |
11 | 20595407693 |
12 | a36978b1a4 |
13 | 501978bb57 |
14 | 28005b8336 |
15 | 15ae76d91a |
hex | c5ee2f74c |
53131540300 has 72 divisors (see below), whose sum is σ = 115933204800. Its totient is φ = 21135313920.
The previous prime is 53131540271. The next prime is 53131540337. The reversal of 53131540300 is 304513135.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 35586354 + ... + 35587846.
It is an arithmetic number, because the mean of its divisors is an integer number (1610183400).
Almost surely, 253131540300 is an apocalyptic number.
53131540300 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
53131540300 is an abundant number, since it is smaller than the sum of its proper divisors (62801664500).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53131540300 is a wasteful number, since it uses less digits than its factorization.
53131540300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3235 (or 3228 counting only the distinct ones).
The product of its (nonzero) digits is 2700, while the sum is 25.
The spelling of 53131540300 in words is "fifty-three billion, one hundred thirty-one million, five hundred forty thousand, three hundred".
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