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53132212401 = 317710737467
BaseRepresentation
bin110001011110111011…
…010011100010110001
312002010212122001021120
4301132323103202301
51332303321244101
640224131412453
73560444232222
oct613673234261
9162125561246
1053132212401
1120595826644
12a369a54129
135019965a48
142800711249
1515ae852b36
hexc5eed38b1

53132212401 has 4 divisors (see below), whose sum is σ = 70842949872. Its totient is φ = 35421474932.

The previous prime is 53132212391. The next prime is 53132212433. The reversal of 53132212401 is 10421223135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53132212401 - 211 = 53132210353 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (53132213401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8855368731 + ... + 8855368736.

It is an arithmetic number, because the mean of its divisors is an integer number (17710737468).

Almost surely, 253132212401 is an apocalyptic number.

It is an amenable number.

53132212401 is a deficient number, since it is larger than the sum of its proper divisors (17710737471).

53132212401 is a wasteful number, since it uses less digits than its factorization.

53132212401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17710737470.

The product of its (nonzero) digits is 1440, while the sum is 24.

Adding to 53132212401 its reverse (10421223135), we get a palindrome (63553435536).

The spelling of 53132212401 in words is "fifty-three billion, one hundred thirty-two million, two hundred twelve thousand, four hundred one".

Divisors: 1 3 17710737467 53132212401