Base | Representation |
---|---|
bin | 100110101010001111110… |
… | …0001100110001111101101 |
3 | 200210221211012222202211121 |
4 | 1031110133201212033231 |
5 | 1144023322240240003 |
6 | 15144535512020541 |
7 | 1055611043046340 |
oct | 115243741461755 |
9 | 20727735882747 |
10 | 5313403446253 |
11 | 17694467a8371 |
12 | 719934091751 |
13 | 2c7089a41956 |
14 | 145254a74457 |
15 | 93331976cbd |
hex | 4d51f8663ed |
5313403446253 has 8 divisors (see below), whose sum is σ = 6145623263808. Its totient is φ = 4499474174304.
The previous prime is 5313403446157. The next prime is 5313403446319. The reversal of 5313403446253 is 3526443043135.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5313403446253 - 29 = 5313403445741 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5313403446353) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4572635776 + ... + 4572636937.
It is an arithmetic number, because the mean of its divisors is an integer number (768202907976).
Almost surely, 25313403446253 is an apocalyptic number.
It is an amenable number.
5313403446253 is a deficient number, since it is larger than the sum of its proper divisors (832219817555).
5313403446253 is an equidigital number, since it uses as much as digits as its factorization.
5313403446253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9145272803.
The product of its (nonzero) digits is 1555200, while the sum is 43.
Adding to 5313403446253 its reverse (3526443043135), we get a palindrome (8839846489388).
The spelling of 5313403446253 in words is "five trillion, three hundred thirteen billion, four hundred three million, four hundred forty-six thousand, two hundred fifty-three".
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