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53134401151 = 1319215119033
BaseRepresentation
bin110001011111000011…
…101001111001111111
312002011000202020200101
4301133003221321333
51332304401314101
640224250341531
73560501646346
oct613703517177
9162130666611
1053134401151
1120596a91027
12a36a72a8a7
13501a251070
142800b20b5d
1515aeb36401
hexc5f0e9e7f

53134401151 has 8 divisors (see below), whose sum is σ = 60233329520. Its totient is φ = 46465710912.

The previous prime is 53134401077. The next prime is 53134401161. The reversal of 53134401151 is 15110443135.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 53134401151 - 231 = 50986917503 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53134401161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 107559270 + ... + 107559763.

It is an arithmetic number, because the mean of its divisors is an integer number (7529166190).

Almost surely, 253134401151 is an apocalyptic number.

53134401151 is a deficient number, since it is larger than the sum of its proper divisors (7098928369).

53134401151 is a wasteful number, since it uses less digits than its factorization.

53134401151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 215119065.

The product of its (nonzero) digits is 3600, while the sum is 28.

Adding to 53134401151 its reverse (15110443135), we get a palindrome (68244844286).

The spelling of 53134401151 in words is "fifty-three billion, one hundred thirty-four million, four hundred one thousand, one hundred fifty-one".

Divisors: 1 13 19 247 215119033 2796547429 4087261627 53134401151