53134421300131 has 4 divisors (see below), whose sum is σ = 53134878412000. Its totient is φ = 53133964188264.

The previous prime is 53134421300069. The next prime is 53134421300179. The reversal of 53134421300131 is 13100312443135.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53134421300131 - 2²³ = 53134412911523 is a prime.

It is a super-2 number, since 2×53134421300131² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53134421300093 and 53134421300102.

It is not an unprimeable number, because it can be changed into a prime (53134421300231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 228381531 + ... + 228614068.

It is an arithmetic number, because the mean of its divisors is an integer number (13283719603000).

Almost surely, 2^{53134421300131} is an apocalyptic number.

53134421300131 is a deficient number, since it is larger than the sum of its proper divisors (457111869).

53134421300131 is a wasteful number, since it uses less digits than its factorization.

53134421300131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 457111868.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 53134421300131 its reverse (13100312443135), we get a palindrome (66234733743266).

The spelling of 53134421300131 in words is "fifty-three trillion, one hundred thirty-four billion, four hundred twenty-one million, three hundred thousand, one hundred thirty-one".