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53134421300179 is a prime number
BaseRepresentation
bin11000001010011010100100…
…10011101001001111010011
320222010121020011211002212021
430011031102103221033103
523431023243323101204
6305001341031512311
714122556331033442
oct1405152223511723
9228117204732767
1053134421300179
1115a261aa68118a
125b61982228697
13238572910784b
14d19a10c6ad59
1562223545c154
hex3053524e93d3

53134421300179 has 2 divisors, whose sum is σ = 53134421300180. Its totient is φ = 53134421300178.

The previous prime is 53134421300069. The next prime is 53134421300197. The reversal of 53134421300179 is 97100312443135.

Together with next prime (53134421300197) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 53134421300179 - 241 = 50935398044627 is a prime.

It is not a weakly prime, because it can be changed into another prime (53134421300579) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26567210650089 + 26567210650090.

It is an arithmetic number, because the mean of its divisors is an integer number (26567210650090).

Almost surely, 253134421300179 is an apocalyptic number.

53134421300179 is a deficient number, since it is larger than the sum of its proper divisors (1).

53134421300179 is an equidigital number, since it uses as much as digits as its factorization.

53134421300179 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 272160, while the sum is 43.

The spelling of 53134421300179 in words is "fifty-three trillion, one hundred thirty-four billion, four hundred twenty-one million, three hundred thousand, one hundred seventy-nine".