Base | Representation |
---|---|
bin | 110001011111001010… |
… | …101111001111101111 |
3 | 12002011011020120211201 |
4 | 301133022233033233 |
5 | 1332310340224111 |
6 | 40224354230331 |
7 | 3560523512113 |
oct | 613712571757 |
9 | 162134216751 |
10 | 53136258031 |
11 | 2059803a13a |
12 | a36b2853a7 |
13 | 501a7512cc |
14 | 2801085743 |
15 | 15aeda16c1 |
hex | c5f2af3ef |
53136258031 has 4 divisors (see below), whose sum is σ = 53140320864. Its totient is φ = 53132195200.
The previous prime is 53136257987. The next prime is 53136258067. The reversal of 53136258031 is 13085263135.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53136258031 - 27 = 53136257903 is a prime.
It is a super-2 number, since 2×531362580312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53136258731) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2011735 + ... + 2037976.
It is an arithmetic number, because the mean of its divisors is an integer number (13285080216).
Almost surely, 253136258031 is an apocalyptic number.
53136258031 is a deficient number, since it is larger than the sum of its proper divisors (4062833).
53136258031 is a wasteful number, since it uses less digits than its factorization.
53136258031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4062832.
The product of its (nonzero) digits is 64800, while the sum is 37.
The spelling of 53136258031 in words is "fifty-three billion, one hundred thirty-six million, two hundred fifty-eight thousand, thirty-one".
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