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5314003343153 = 9051975870549
BaseRepresentation
bin100110101010100001101…
…0010000001011100110001
3200211000101000210200200022
41031111003102001130301
51144031034323440103
615145115221533225
71055631646066031
oct115250322013461
920730330720608
105314003343153
11176972439582a
12719a80b74215
132c715410262b
141452b05d18c1
1593369474138
hex4d543481731

5314003343153 has 4 divisors (see below), whose sum is σ = 5314010118900. Its totient is φ = 5313996567408.

The previous prime is 5314003343147. The next prime is 5314003343161. The reversal of 5314003343153 is 3513433004135.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 789142625569 + 4524860717584 = 888337^2 + 2127172^2 .

It is a cyclic number.

It is not a de Polignac number, because 5314003343153 - 220 = 5314002294577 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5314003343353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2030078 + ... + 3840471.

It is an arithmetic number, because the mean of its divisors is an integer number (1328502529725).

Almost surely, 25314003343153 is an apocalyptic number.

It is an amenable number.

5314003343153 is a deficient number, since it is larger than the sum of its proper divisors (6775747).

5314003343153 is an equidigital number, since it uses as much as digits as its factorization.

5314003343153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6775746.

The product of its (nonzero) digits is 97200, while the sum is 35.

Adding to 5314003343153 its reverse (3513433004135), we get a palindrome (8827436347288).

The spelling of 5314003343153 in words is "five trillion, three hundred fourteen billion, three million, three hundred forty-three thousand, one hundred fifty-three".

Divisors: 1 905197 5870549 5314003343153