Base | Representation |
---|---|
bin | 1111011101110011110… |
… | …11101001110010101011 |
3 | 1212210122012121022022220 |
4 | 13232321323221302223 |
5 | 32201302000300133 |
6 | 1044042202445123 |
7 | 53251411605222 |
oct | 7567173516253 |
9 | 1783565538286 |
10 | 531400400043 |
11 | 195402743837 |
12 | 86ba4b037a3 |
13 | 3b1596a1746 |
14 | 1ba11645cb9 |
15 | dc526805b3 |
hex | 7bb9ee9cab |
531400400043 has 4 divisors (see below), whose sum is σ = 708533866728. Its totient is φ = 354266933360.
The previous prime is 531400400039. The next prime is 531400400051. The reversal of 531400400043 is 340004004135.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 531400400043 - 22 = 531400400039 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 531400399986 and 531400400022.
It is not an unprimeable number, because it can be changed into a prime (531400400093) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88566733338 + ... + 88566733343.
It is an arithmetic number, because the mean of its divisors is an integer number (177133466682).
Almost surely, 2531400400043 is an apocalyptic number.
531400400043 is a deficient number, since it is larger than the sum of its proper divisors (177133466685).
531400400043 is a wasteful number, since it uses less digits than its factorization.
531400400043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 177133466684.
The product of its (nonzero) digits is 2880, while the sum is 24.
Adding to 531400400043 its reverse (340004004135), we get a palindrome (871404404178).
The spelling of 531400400043 in words is "five hundred thirty-one billion, four hundred million, four hundred thousand, forty-three".
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