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531400400101 = 1792968717319
BaseRepresentation
bin1111011101110011110…
…11101001110011100101
31212210122012121022102001
413232321323221303211
532201302000300401
61044042202445301
753251411605334
oct7567173516345
91783565538361
10531400400101
1119540274388a
1286ba4b03831
133b1596a178c
141ba11645d1b
15dc52680601
hex7bb9ee9ce5

531400400101 has 4 divisors (see below), whose sum is σ = 534369117600. Its totient is φ = 528431682604.

The previous prime is 531400400099. The next prime is 531400400117. The reversal of 531400400101 is 101004004135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 531400400101 - 21 = 531400400099 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (531400400131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1484358481 + ... + 1484358838.

It is an arithmetic number, because the mean of its divisors is an integer number (133592279400).

Almost surely, 2531400400101 is an apocalyptic number.

It is an amenable number.

531400400101 is a deficient number, since it is larger than the sum of its proper divisors (2968717499).

531400400101 is a wasteful number, since it uses less digits than its factorization.

531400400101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2968717498.

The product of its (nonzero) digits is 240, while the sum is 19.

Adding to 531400400101 its reverse (101004004135), we get a palindrome (632404404236).

The spelling of 531400400101 in words is "five hundred thirty-one billion, four hundred million, four hundred thousand, one hundred one".

Divisors: 1 179 2968717319 531400400101