Base | Representation |
---|---|
bin | 1111011101110011110… |
… | …11101001110011100101 |
3 | 1212210122012121022102001 |
4 | 13232321323221303211 |
5 | 32201302000300401 |
6 | 1044042202445301 |
7 | 53251411605334 |
oct | 7567173516345 |
9 | 1783565538361 |
10 | 531400400101 |
11 | 19540274388a |
12 | 86ba4b03831 |
13 | 3b1596a178c |
14 | 1ba11645d1b |
15 | dc52680601 |
hex | 7bb9ee9ce5 |
531400400101 has 4 divisors (see below), whose sum is σ = 534369117600. Its totient is φ = 528431682604.
The previous prime is 531400400099. The next prime is 531400400117. The reversal of 531400400101 is 101004004135.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 531400400101 - 21 = 531400400099 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (531400400131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1484358481 + ... + 1484358838.
It is an arithmetic number, because the mean of its divisors is an integer number (133592279400).
Almost surely, 2531400400101 is an apocalyptic number.
It is an amenable number.
531400400101 is a deficient number, since it is larger than the sum of its proper divisors (2968717499).
531400400101 is a wasteful number, since it uses less digits than its factorization.
531400400101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2968717498.
The product of its (nonzero) digits is 240, while the sum is 19.
Adding to 531400400101 its reverse (101004004135), we get a palindrome (632404404236).
The spelling of 531400400101 in words is "five hundred thirty-one billion, four hundred million, four hundred thousand, one hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.084 sec. • engine limits •