Base | Representation |
---|---|
bin | 1111011101110011110… |
… | …11101001111000011011 |
3 | 1212210122012121022211112 |
4 | 13232321323221320123 |
5 | 32201302000303121 |
6 | 1044042202450535 |
7 | 53251411606256 |
oct | 7567173517033 |
9 | 1783565538745 |
10 | 531400400411 |
11 | 195402744041 |
12 | 86ba4b03a4b |
13 | 3b1596a196a |
14 | 1ba1164609d |
15 | dc5268075b |
hex | 7bb9ee9e1b |
531400400411 has 4 divisors (see below), whose sum is σ = 562659247512. Its totient is φ = 500141553312.
The previous prime is 531400400387. The next prime is 531400400417. The reversal of 531400400411 is 114004004135.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-531400400411 is a prime.
It is a super-2 number, since 2×5314004004112 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (531400400417) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15629423525 + ... + 15629423558.
It is an arithmetic number, because the mean of its divisors is an integer number (140664811878).
Almost surely, 2531400400411 is an apocalyptic number.
531400400411 is a deficient number, since it is larger than the sum of its proper divisors (31258847101).
531400400411 is a wasteful number, since it uses less digits than its factorization.
531400400411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31258847100.
The product of its (nonzero) digits is 960, while the sum is 23.
Adding to 531400400411 its reverse (114004004135), we get a palindrome (645404404546).
The spelling of 531400400411 in words is "five hundred thirty-one billion, four hundred million, four hundred thousand, four hundred eleven".
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