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531400400411 = 1731258847083
BaseRepresentation
bin1111011101110011110…
…11101001111000011011
31212210122012121022211112
413232321323221320123
532201302000303121
61044042202450535
753251411606256
oct7567173517033
91783565538745
10531400400411
11195402744041
1286ba4b03a4b
133b1596a196a
141ba1164609d
15dc5268075b
hex7bb9ee9e1b

531400400411 has 4 divisors (see below), whose sum is σ = 562659247512. Its totient is φ = 500141553312.

The previous prime is 531400400387. The next prime is 531400400417. The reversal of 531400400411 is 114004004135.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-531400400411 is a prime.

It is a super-2 number, since 2×5314004004112 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (531400400417) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15629423525 + ... + 15629423558.

It is an arithmetic number, because the mean of its divisors is an integer number (140664811878).

Almost surely, 2531400400411 is an apocalyptic number.

531400400411 is a deficient number, since it is larger than the sum of its proper divisors (31258847101).

531400400411 is a wasteful number, since it uses less digits than its factorization.

531400400411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31258847100.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 531400400411 its reverse (114004004135), we get a palindrome (645404404546).

The spelling of 531400400411 in words is "five hundred thirty-one billion, four hundred million, four hundred thousand, four hundred eleven".

Divisors: 1 17 31258847083 531400400411