Base | Representation |
---|---|
bin | 1111011101110011110… |
… | …11101001111000100001 |
3 | 1212210122012121022211202 |
4 | 13232321323221320201 |
5 | 32201302000303132 |
6 | 1044042202450545 |
7 | 53251411606265 |
oct | 7567173517041 |
9 | 1783565538752 |
10 | 531400400417 |
11 | 195402744047 |
12 | 86ba4b03a55 |
13 | 3b1596a1973 |
14 | 1ba116460a5 |
15 | dc52680762 |
hex | 7bb9ee9e21 |
531400400417 has 2 divisors, whose sum is σ = 531400400418. Its totient is φ = 531400400416.
The previous prime is 531400400387. The next prime is 531400400423. The reversal of 531400400417 is 714004004135.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 511269330961 + 20131069456 = 715031^2 + 141884^2 .
It is a cyclic number.
It is not a de Polignac number, because 531400400417 - 226 = 531333291553 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 531400400417.
It is not a weakly prime, because it can be changed into another prime (531400400437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265700200208 + 265700200209.
It is an arithmetic number, because the mean of its divisors is an integer number (265700200209).
Almost surely, 2531400400417 is an apocalyptic number.
It is an amenable number.
531400400417 is a deficient number, since it is larger than the sum of its proper divisors (1).
531400400417 is an equidigital number, since it uses as much as digits as its factorization.
531400400417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6720, while the sum is 29.
The spelling of 531400400417 in words is "five hundred thirty-one billion, four hundred million, four hundred thousand, four hundred seventeen".
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