Base | Representation |
---|---|
bin | 11000001010100101000010… |
… | …10110001001101000011111 |
3 | 20222011010201220202201122122 |
4 | 30011102201112021220133 |
5 | 23431121301313341021 |
6 | 305004110505533155 |
7 | 14123145533663462 |
oct | 1405224126115037 |
9 | 228133656681578 |
10 | 53140042324511 |
11 | 15a28624596a3a |
12 | 5b62a907a41bb |
13 | 238611381374c |
14 | d19dc55c92d9 |
15 | 622463b85bab |
hex | 3054a1589a1f |
53140042324511 has 8 divisors (see below), whose sum is σ = 55939118119920. Its totient is φ = 50341189675392.
The previous prime is 53140042324463. The next prime is 53140042324513. The reversal of 53140042324511 is 11542324004135.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53140042324511 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53140042324513) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 55297640 + ... + 56250413.
It is an arithmetic number, because the mean of its divisors is an integer number (6992389764990).
Almost surely, 253140042324511 is an apocalyptic number.
53140042324511 is a deficient number, since it is larger than the sum of its proper divisors (2799075795409).
53140042324511 is a wasteful number, since it uses less digits than its factorization.
53140042324511 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 111573145.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 53140042324511 its reverse (11542324004135), we get a palindrome (64682366328646).
The spelling of 53140042324511 in words is "fifty-three trillion, one hundred forty billion, forty-two million, three hundred twenty-four thousand, five hundred eleven".
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