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53140114 = 226570057
BaseRepresentation
bin1100101010110…
…1101010010010
310200222210112101
43022231222102
5102100440424
65134551014
71213453306
oct312555222
9120883471
1053140114
1127aa5a55
121596846a
13b017771
1470b3d06
1549ea344
hex32ada92

53140114 has 4 divisors (see below), whose sum is σ = 79710174. Its totient is φ = 26570056.

The previous prime is 53140111. The next prime is 53140121. The reversal of 53140114 is 41104135.

53140114 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 48539089 + 4601025 = 6967^2 + 2145^2 .

It is a junction number, because it is equal to n+sod(n) for n = 53140091 and 53140100.

It is not an unprimeable number, because it can be changed into a prime (53140111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13285027 + ... + 13285030.

Almost surely, 253140114 is an apocalyptic number.

53140114 is a deficient number, since it is larger than the sum of its proper divisors (26570060).

53140114 is a wasteful number, since it uses less digits than its factorization.

53140114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26570059.

The product of its (nonzero) digits is 240, while the sum is 19.

The square root of 53140114 is about 7289.7266066705. The cubic root of 53140114 is about 375.9592956163.

Adding to 53140114 its reverse (41104135), we get a palindrome (94244249).

The spelling of 53140114 in words is "fifty-three million, one hundred forty thousand, one hundred fourteen".

Divisors: 1 2 26570057 53140114