Base | Representation |
---|---|
bin | 11000001010100101001111… |
… | …00100000101010011101111 |
3 | 20222011011000012001111202101 |
4 | 30011102213210011103233 |
5 | 23431122010014440421 |
6 | 305004125113435531 |
7 | 14123151241441546 |
oct | 1405224744052357 |
9 | 228134005044671 |
10 | 53140146640111 |
11 | 15a28678465883 |
12 | 5b62abb70bba7 |
13 | 238612c30865b |
14 | d19dd53c115d |
15 | 62246cdde191 |
hex | 3054a79054ef |
53140146640111 has 8 divisors (see below), whose sum is σ = 54972714139200. Its totient is φ = 51307589051040.
The previous prime is 53140146640069. The next prime is 53140146640121. The reversal of 53140146640111 is 11104664104135.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53140146640111 - 235 = 53105786901743 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53140146640121) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9396585 + ... + 13949053.
It is an arithmetic number, because the mean of its divisors is an integer number (6871589267400).
Almost surely, 253140146640111 is an apocalyptic number.
53140146640111 is a deficient number, since it is larger than the sum of its proper divisors (1832567499089).
53140146640111 is a wasteful number, since it uses less digits than its factorization.
53140146640111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4955009.
The product of its (nonzero) digits is 34560, while the sum is 37.
The spelling of 53140146640111 in words is "fifty-three trillion, one hundred forty billion, one hundred forty-six million, six hundred forty thousand, one hundred eleven".
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