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53143112121 = 3111610397337
BaseRepresentation
bin110001011111100100…
…111000100110111001
312002011122010210212220
4301133210320212321
51332314114041441
640225201154253
73560635666641
oct613744704671
9162148123786
1053143112121
11205a09a0780
12a37162b989
13501bcb0c98
142801d4b521
1515b07a7466
hexc5f9389b9

53143112121 has 8 divisors (see below), whose sum is σ = 77299072224. Its totient is φ = 32207946720.

The previous prime is 53143112117. The next prime is 53143112167. The reversal of 53143112121 is 12121134135.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 53143112121 - 22 = 53143112117 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 53143112091 and 53143112100.

It is not an unprimeable number, because it can be changed into a prime (53143114121) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 805198636 + ... + 805198701.

It is an arithmetic number, because the mean of its divisors is an integer number (9662384028).

Almost surely, 253143112121 is an apocalyptic number.

It is an amenable number.

53143112121 is a deficient number, since it is larger than the sum of its proper divisors (24155960103).

53143112121 is a wasteful number, since it uses less digits than its factorization.

53143112121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1610397351.

The product of its digits is 720, while the sum is 24.

Adding to 53143112121 its reverse (12121134135), we get a palindrome (65264246256).

The spelling of 53143112121 in words is "fifty-three billion, one hundred forty-three million, one hundred twelve thousand, one hundred twenty-one".

Divisors: 1 3 11 33 1610397337 4831192011 17714370707 53143112121