Base | Representation |
---|---|
bin | 1111011101110111111… |
… | …00011010010000110011 |
3 | 1212210201120010010200211 |
4 | 13232323330122100303 |
5 | 32201334120344021 |
6 | 1044045410124551 |
7 | 53252301524326 |
oct | 7567374322063 |
9 | 1783646103624 |
10 | 531434153011 |
11 | 19541a7a7953 |
12 | 86bb4280757 |
13 | 3b16368ba08 |
14 | 1ba15d107bd |
15 | dc555eb3e1 |
hex | 7bbbf1a433 |
531434153011 has 8 divisors (see below), whose sum is σ = 534675700944. Its totient is φ = 528202414080.
The previous prime is 531434152961. The next prime is 531434153017. The reversal of 531434153011 is 110351434135.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 531434153011 - 211 = 531434150963 is a prime.
It is a super-2 number, since 2×5314341530112 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (531434153017) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2343550 + ... + 2560291.
It is an arithmetic number, because the mean of its divisors is an integer number (66834462618).
Almost surely, 2531434153011 is an apocalyptic number.
531434153011 is a deficient number, since it is larger than the sum of its proper divisors (3241547933).
531434153011 is a wasteful number, since it uses less digits than its factorization.
531434153011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4904501.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 531434153011 its reverse (110351434135), we get a palindrome (641785587146).
The spelling of 531434153011 in words is "five hundred thirty-one billion, four hundred thirty-four million, one hundred fifty-three thousand, eleven".
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