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5314433111 = 13408802547
BaseRepresentation
bin1001111001100001…
…11101000001010111
3111201101001011200222
410330300331001113
541340443324421
62235202424555
7245460636041
oct47460750127
914641034628
105314433111
11228794a289
12104396215b
13669040ca0
14385b50a91
15211866cab
hex13cc3d057

5314433111 has 4 divisors (see below), whose sum is σ = 5723235672. Its totient is φ = 4905630552.

The previous prime is 5314433101. The next prime is 5314433123. The reversal of 5314433111 is 1113344135.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5314433111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5314433101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 204401261 + ... + 204401286.

It is an arithmetic number, because the mean of its divisors is an integer number (1430808918).

Almost surely, 25314433111 is an apocalyptic number.

5314433111 is a deficient number, since it is larger than the sum of its proper divisors (408802561).

5314433111 is a wasteful number, since it uses less digits than its factorization.

5314433111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 408802560.

The product of its digits is 2160, while the sum is 26.

The square root of 5314433111 is about 72900.1585114875. The cubic root of 5314433111 is about 1745.0946285741.

Adding to 5314433111 its reverse (1113344135), we get a palindrome (6427777246).

The spelling of 5314433111 in words is "five billion, three hundred fourteen million, four hundred thirty-three thousand, one hundred eleven".

Divisors: 1 13 408802547 5314433111