Base | Representation |
---|---|
bin | 100110101010101110101… |
… | …1100100001101110001111 |
3 | 200211001111121210020022020 |
4 | 1031111131130201232033 |
5 | 1144032434212220044 |
6 | 15145230542221223 |
7 | 1055645556151314 |
oct | 115253534415617 |
9 | 20731447706266 |
10 | 5314442304399 |
11 | 176992a151918 |
12 | 719b83b84813 |
13 | 2c71c4035a07 |
14 | 145312a18d0b |
15 | 93392c81a19 |
hex | 4d55d721b8f |
5314442304399 has 4 divisors (see below), whose sum is σ = 7085923072536. Its totient is φ = 3542961536264.
The previous prime is 5314442304397. The next prime is 5314442304407. The reversal of 5314442304399 is 9934032444135.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5314442304399 - 21 = 5314442304397 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5314442304397) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 885740384064 + ... + 885740384069.
It is an arithmetic number, because the mean of its divisors is an integer number (1771480768134).
Almost surely, 25314442304399 is an apocalyptic number.
5314442304399 is a deficient number, since it is larger than the sum of its proper divisors (1771480768137).
5314442304399 is a wasteful number, since it uses less digits than its factorization.
5314442304399 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1771480768136.
The product of its (nonzero) digits is 5598720, while the sum is 51.
The spelling of 5314442304399 in words is "five trillion, three hundred fourteen billion, four hundred forty-two million, three hundred four thousand, three hundred ninety-nine".
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