Base | Representation |
---|---|
bin | 100110101010110001011… |
… | …1010110110110100010001 |
3 | 200211001202000121000201021 |
4 | 1031111202322312310101 |
5 | 1144033131220004301 |
6 | 15145244022435441 |
7 | 1055651052564145 |
oct | 115254272666421 |
9 | 20731660530637 |
10 | 5314534141201 |
11 | 1769976a781aa |
12 | 719baa892b81 |
13 | 2c720a07ba0c |
14 | 145320cc3225 |
15 | 9339ad728a1 |
hex | 4d562eb6d11 |
5314534141201 has 8 divisors (see below), whose sum is σ = 5337908470080. Its totient is φ = 5291161262832.
The previous prime is 5314534141181. The next prime is 5314534141243. The reversal of 5314534141201 is 1021414354135.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5314534141201 - 217 = 5314534010129 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5314534141801) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7340196 + ... + 8031658.
It is an arithmetic number, because the mean of its divisors is an integer number (667238558760).
Almost surely, 25314534141201 is an apocalyptic number.
It is an amenable number.
5314534141201 is a deficient number, since it is larger than the sum of its proper divisors (23374328879).
5314534141201 is a wasteful number, since it uses less digits than its factorization.
5314534141201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 725255.
The product of its (nonzero) digits is 28800, while the sum is 34.
Adding to 5314534141201 its reverse (1021414354135), we get a palindrome (6335948495336).
The spelling of 5314534141201 in words is "five trillion, three hundred fourteen billion, five hundred thirty-four million, one hundred forty-one thousand, two hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •