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5314966720800 = 2535211223898941
BaseRepresentation
bin100110101010111110010…
…1101000001000100100000
3200211002212011120100100220
41031111330231001010200
51144040022440031200
615145354554243040
71055664554500152
oct115257455010440
920732764510326
105314966720800
11176a079175700
1271a0ab726480
132c7278889489
14145362528ad2
15933c3d1e4a0
hex4d57cb41120

5314966720800 has 864 divisors, whose sum is σ = 20067916821120. Its totient is φ = 1218471936000.

The previous prime is 5314966720781. The next prime is 5314966720871. The reversal of 5314966720800 is 80276694135.

It is an unprimeable number.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 594444330 + ... + 594453270.

It is an arithmetic number, because the mean of its divisors is an integer number (23226755580).

It is a 1-persistent number, because it is pandigital, but 2⋅5314966720800 = 10629933441600 is not.

Almost surely, 25314966720800 is an apocalyptic number.

5314966720800 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 5314966720800, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (10033958410560).

5314966720800 is an abundant number, since it is smaller than the sum of its proper divisors (14752950100320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

5314966720800 is a wasteful number, since it uses less digits than its factorization.

5314966720800 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9098 (or 9074 counting only the distinct ones).

The product of its (nonzero) digits is 2177280, while the sum is 51.

The spelling of 5314966720800 in words is "five trillion, three hundred fourteen billion, nine hundred sixty-six million, seven hundred twenty thousand, eight hundred".