Base | Representation |
---|---|
bin | 11000001010111010000001… |
… | …00110001010001110000011 |
3 | 20222012012210202122210122210 |
4 | 30011131000212022032003 |
5 | 23431312332313030110 |
6 | 305013212203233203 |
7 | 14124024601635336 |
oct | 1405350046121603 |
9 | 228165722583583 |
10 | 53151304033155 |
11 | 15a32383525369 |
12 | 5b650b4218803 |
13 | 23871b9a1cc83 |
14 | d1a77314261d |
15 | 6228c26bd520 |
hex | 30574098a383 |
53151304033155 has 64 divisors (see below), whose sum is σ = 85590288000000. Its totient is φ = 28165388262912.
The previous prime is 53151304033151. The next prime is 53151304033211. The reversal of 53151304033155 is 55133040315135.
It is not a de Polignac number, because 53151304033155 - 22 = 53151304033151 is a prime.
It is a super-3 number, since 3×531513040331553 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (53151304033151) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1705793466 + ... + 1705824624.
It is an arithmetic number, because the mean of its divisors is an integer number (1337348250000).
Almost surely, 253151304033155 is an apocalyptic number.
53151304033155 is a deficient number, since it is larger than the sum of its proper divisors (32438983966845).
53151304033155 is a wasteful number, since it uses less digits than its factorization.
53151304033155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32668.
The product of its (nonzero) digits is 202500, while the sum is 39.
The spelling of 53151304033155 in words is "fifty-three trillion, one hundred fifty-one billion, three hundred four million, thirty-three thousand, one hundred fifty-five".
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