Base | Representation |
---|---|
bin | 11000001010111010110100… |
… | …01001100100100110001111 |
3 | 20222012020220122100200222222 |
4 | 30011131122021210212033 |
5 | 23431314222040343024 |
6 | 305013322520125555 |
7 | 14124041325640022 |
oct | 1405353211444617 |
9 | 228166818320888 |
10 | 53151732746639 |
11 | 15a3258352212a |
12 | 5b651b39068bb |
13 | 23872577a5aa7 |
14 | d1a7b405d1b9 |
15 | 6228ea15485e |
hex | 30575a26498f |
53151732746639 has 4 divisors (see below), whose sum is σ = 53151781890024. Its totient is φ = 53151683603256.
The previous prime is 53151732746627. The next prime is 53151732746647. The reversal of 53151732746639 is 93664723715135.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53151732746639 is a prime.
It is a super-2 number, since 2×531517327466392 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53151732746659) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22911977 + ... + 25124930.
It is an arithmetic number, because the mean of its divisors is an integer number (13287945472506).
Almost surely, 253151732746639 is an apocalyptic number.
53151732746639 is a deficient number, since it is larger than the sum of its proper divisors (49143385).
53151732746639 is a wasteful number, since it uses less digits than its factorization.
53151732746639 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49143384.
The product of its digits is 85730400, while the sum is 62.
The spelling of 53151732746639 in words is "fifty-three trillion, one hundred fifty-one billion, seven hundred thirty-two million, seven hundred forty-six thousand, six hundred thirty-nine".
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