Base | Representation |
---|---|
bin | 111100011011011010010101… |
… | …1101010001111100010010101 |
3 | 2120201000001120200111121022110 |
4 | 1320312310223222033202111 |
5 | 1024132114041014120140 |
6 | 5122250520030221233 |
7 | 216646664151650103 |
oct | 17066645352174225 |
9 | 2521001520447273 |
10 | 531533000145045 |
11 | 1443a99745aa658 |
12 | 4b7467a6354819 |
13 | 19a78468016b82 |
14 | 9538497b20c73 |
15 | 416b5d6c6c380 |
hex | 1e36d2ba8f895 |
531533000145045 has 16 divisors (see below), whose sum is σ = 858709623537792. Its totient is φ = 280731992308800.
The previous prime is 531533000145041. The next prime is 531533000145089. The reversal of 531533000145045 is 540541000335135.
It is not a de Polignac number, because 531533000145045 - 22 = 531533000145041 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 531533000144994 and 531533000145012.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (531533000145041) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 172017150606 + ... + 172017153695.
It is an arithmetic number, because the mean of its divisors is an integer number (53669351471112).
Almost surely, 2531533000145045 is an apocalyptic number.
It is an amenable number.
531533000145045 is a deficient number, since it is larger than the sum of its proper divisors (327176623392747).
531533000145045 is a wasteful number, since it uses less digits than its factorization.
531533000145045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 344034304412.
The product of its (nonzero) digits is 270000, while the sum is 39.
The spelling of 531533000145045 in words is "five hundred thirty-one trillion, five hundred thirty-three billion, one hundred forty-five thousand, forty-five".
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