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5315431121401 = 19127829482311
BaseRepresentation
bin100110101011001100001…
…1000100100000111111001
3200211011001112102100020011
41031112120120210013321
51144042000331341101
615145513024101521
71056012224024602
oct115263030440771
920734045370204
105315431121401
11176a297327755
1271a1bb1648a1
132c7320b58a2b
141453a8094da9
15933ee9a4751
hex4d5986241f9

5315431121401 has 4 divisors (see below), whose sum is σ = 5343260603904. Its totient is φ = 5287601638900.

The previous prime is 5315431121393. The next prime is 5315431121501. The reversal of 5315431121401 is 1041211345135.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5315431121401 - 23 = 5315431121393 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5315431121501) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13914740965 + ... + 13914741346.

It is an arithmetic number, because the mean of its divisors is an integer number (1335815150976).

Almost surely, 25315431121401 is an apocalyptic number.

It is an amenable number.

5315431121401 is a deficient number, since it is larger than the sum of its proper divisors (27829482503).

5315431121401 is a wasteful number, since it uses less digits than its factorization.

5315431121401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27829482502.

The product of its (nonzero) digits is 7200, while the sum is 31.

Adding to 5315431121401 its reverse (1041211345135), we get a palindrome (6356642466536).

The spelling of 5315431121401 in words is "five trillion, three hundred fifteen billion, four hundred thirty-one million, one hundred twenty-one thousand, four hundred one".

Divisors: 1 191 27829482311 5315431121401