Base | Representation |
---|---|
bin | 100110101011010111001… |
… | …1000010100101111011011 |
3 | 200211012000020211022002202 |
4 | 1031112232120110233123 |
5 | 1144043224320012042 |
6 | 15150013405520415 |
7 | 1056024324543554 |
oct | 115265630245733 |
9 | 20735006738082 |
10 | 5315800157147 |
11 | 176a466673777 |
12 | 71a2a287310b |
13 | 2c737c44848c |
14 | 1454010b932b |
15 | 9342209d632 |
hex | 4d5ae614bdb |
5315800157147 has 4 divisors (see below), whose sum is σ = 5628494284056. Its totient is φ = 5003106030240.
The previous prime is 5315800157119. The next prime is 5315800157159. The reversal of 5315800157147 is 7417510085135.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 5315800157147 - 212 = 5315800153051 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5315802157147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 156347063429 + ... + 156347063462.
It is an arithmetic number, because the mean of its divisors is an integer number (1407123571014).
Almost surely, 25315800157147 is an apocalyptic number.
5315800157147 is a deficient number, since it is larger than the sum of its proper divisors (312694126909).
5315800157147 is a wasteful number, since it uses less digits than its factorization.
5315800157147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 312694126908.
The product of its (nonzero) digits is 588000, while the sum is 47.
The spelling of 5315800157147 in words is "five trillion, three hundred fifteen billion, eight hundred million, one hundred fifty-seven thousand, one hundred forty-seven".
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