Base | Representation |
---|---|
bin | 1111011110001011110… |
… | …01010001010100110101 |
3 | 1212211011012021000211122 |
4 | 13233011321101110311 |
5 | 32202204340232013 |
6 | 1044114132313325 |
7 | 53256366545423 |
oct | 7570571212465 |
9 | 1784135230748 |
10 | 531601102133 |
11 | 1954a5a66232 |
12 | 87040172845 |
13 | 3b18c14348a |
14 | 1ba3016c113 |
15 | dc650c7a08 |
hex | 7bc5e51535 |
531601102133 has 4 divisors (see below), whose sum is σ = 534120538848. Its totient is φ = 529081665420.
The previous prime is 531601102129. The next prime is 531601102141. The reversal of 531601102133 is 331201106135.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 531601102133 - 22 = 531601102129 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (531601102103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1259718041 + ... + 1259718462.
It is an arithmetic number, because the mean of its divisors is an integer number (133530134712).
Almost surely, 2531601102133 is an apocalyptic number.
It is an amenable number.
531601102133 is a deficient number, since it is larger than the sum of its proper divisors (2519436715).
531601102133 is a wasteful number, since it uses less digits than its factorization.
531601102133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2519436714.
The product of its (nonzero) digits is 1620, while the sum is 26.
Adding to 531601102133 its reverse (331201106135), we get a palindrome (862802208268).
The spelling of 531601102133 in words is "five hundred thirty-one billion, six hundred one million, one hundred two thousand, one hundred thirty-three".
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