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53162132161 = 499106537339
BaseRepresentation
bin110001100000101101…
…011100001011000001
312002012221221010110211
4301200231130023001
51332334001212121
640231120554121
73561256444645
oct614055341301
9162187833424
1053162132161
1120600701816
12a377a82941
135022c10348
14280469cc25
1515b22b2ce1
hexc60b5c2c1

53162132161 has 4 divisors (see below), whose sum is σ = 53268670000. Its totient is φ = 53055594324.

The previous prime is 53162132137. The next prime is 53162132213. The reversal of 53162132161 is 16123126135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 16123126135 = 53224625227.

It is a cyclic number.

It is not a de Polignac number, because 53162132161 - 233 = 44572197569 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53162132461) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53268171 + ... + 53269168.

It is an arithmetic number, because the mean of its divisors is an integer number (13317167500).

Almost surely, 253162132161 is an apocalyptic number.

It is an amenable number.

53162132161 is a deficient number, since it is larger than the sum of its proper divisors (106537839).

53162132161 is a wasteful number, since it uses less digits than its factorization.

53162132161 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 106537838.

The product of its digits is 6480, while the sum is 31.

Adding to 53162132161 its reverse (16123126135), we get a palindrome (69285258296).

The spelling of 53162132161 in words is "fifty-three billion, one hundred sixty-two million, one hundred thirty-two thousand, one hundred sixty-one".

Divisors: 1 499 106537339 53162132161