Base | Representation |
---|---|
bin | 11000001011010010010010… |
… | …01101000010110101010111 |
3 | 20222020110102210121110222012 |
4 | 30011221021031002311113 |
5 | 23432021023314034020 |
6 | 305023205122454435 |
7 | 14124665512160504 |
oct | 1405511115026527 |
9 | 228213383543865 |
10 | 53164333346135 |
11 | 15a3795a201020 |
12 | 5b6772b80441b |
13 | 23884b51b601b |
14 | d1b24b73c4ab |
15 | 622dd64b07c5 |
hex | 305a49342d57 |
53164333346135 has 16 divisors (see below), whose sum is σ = 69597368985600. Its totient is φ = 38664734420640.
The previous prime is 53164333346107. The next prime is 53164333346153.
53164333346135 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53164333346135 - 216 = 53164333280599 is a prime.
It is a super-3 number, since 3×531643333461353 (a number of 42 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6449474 + ... + 12162416.
It is an arithmetic number, because the mean of its divisors is an integer number (4349835561600).
Almost surely, 253164333346135 is an apocalyptic number.
53164333346135 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53164333346135 is a deficient number, since it is larger than the sum of its proper divisors (16433035639465).
53164333346135 is a wasteful number, since it uses less digits than its factorization.
53164333346135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5882158.
The product of its digits is 10497600, while the sum is 50.
The spelling of 53164333346135 in words is "fifty-three trillion, one hundred sixty-four billion, three hundred thirty-three million, three hundred forty-six thousand, one hundred thirty-five".
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