Base | Representation |
---|---|
bin | 11000001011100010111011… |
… | …10111111011000010010101 |
3 | 20222021022111121121211222221 |
4 | 30011301131313323002111 |
5 | 23432142324114042201 |
6 | 305031244003422341 |
7 | 14125433126061361 |
oct | 1405613567730225 |
9 | 228238447554887 |
10 | 53173270065301 |
11 | 15a40725800441 |
12 | 5b694046849b1 |
13 | 23892aa80ac29 |
14 | d1b8585a02a1 |
15 | 62325ad3c4a1 |
hex | 305c5ddfb095 |
53173270065301 has 4 divisors (see below), whose sum is σ = 55485151372512. Its totient is φ = 50861388758092.
The previous prime is 53173270065287. The next prime is 53173270065343. The reversal of 53173270065301 is 10356007237135.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 53173270065301 - 217 = 53173269934229 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53173270065371) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1155940653571 + ... + 1155940653616.
It is an arithmetic number, because the mean of its divisors is an integer number (13871287843128).
Almost surely, 253173270065301 is an apocalyptic number.
It is an amenable number.
53173270065301 is a deficient number, since it is larger than the sum of its proper divisors (2311881307211).
53173270065301 is a wasteful number, since it uses less digits than its factorization.
53173270065301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2311881307210.
The product of its (nonzero) digits is 396900, while the sum is 43.
The spelling of 53173270065301 in words is "fifty-three trillion, one hundred seventy-three billion, two hundred seventy million, sixty-five thousand, three hundred one".
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