Base | Representation |
---|---|
bin | 100110101100111101111… |
… | …1110001111001011010001 |
3 | 200211111220122020021012212 |
4 | 1031121323332033023101 |
5 | 1144122310323100410 |
6 | 15151343543401505 |
7 | 1056205650046430 |
oct | 115317376171321 |
9 | 20744818207185 |
10 | 5319249425105 |
11 | 177097669a850 |
12 | 71aaa5a53295 |
13 | 2c77abc31435 |
14 | 14564b22d117 |
15 | 93574cd8b05 |
hex | 4d67bf8f2d1 |
5319249425105 has 64 divisors (see below), whose sum is σ = 8329248976896. Its totient is φ = 3162142368000.
The previous prime is 5319249425099. The next prime is 5319249425167. The reversal of 5319249425105 is 5015249429135.
It is not a de Polignac number, because 5319249425105 - 210 = 5319249424081 is a prime.
It is a super-3 number, since 3×53192494251053 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2023595 + ... + 3838415.
It is an arithmetic number, because the mean of its divisors is an integer number (130144515264).
Almost surely, 25319249425105 is an apocalyptic number.
5319249425105 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
5319249425105 is a deficient number, since it is larger than the sum of its proper divisors (3009999551791).
5319249425105 is a wasteful number, since it uses less digits than its factorization.
5319249425105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1815198.
The product of its (nonzero) digits is 1944000, while the sum is 50.
The spelling of 5319249425105 in words is "five trillion, three hundred nineteen billion, two hundred forty-nine million, four hundred twenty-five thousand, one hundred five".
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