Base | Representation |
---|---|
bin | 110001100010101111… |
… | …101010011001001111 |
3 | 12002022100011110121012 |
4 | 301202233222121033 |
5 | 1332421221103020 |
6 | 40234340355435 |
7 | 3562152553442 |
oct | 614257523117 |
9 | 162270143535 |
10 | 53196269135 |
11 | 206189a8399 |
12 | a3873a5b7b |
13 | 502a003339 |
14 | 2809027659 |
15 | 15b52a77c5 |
hex | c62bea64f |
53196269135 has 8 divisors (see below), whose sum is σ = 63838666320. Its totient is φ = 42554919744.
The previous prime is 53196269089. The next prime is 53196269143.
53196269135 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53196269135 is a prime.
It is a super-3 number, since 3×531962691353 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 145550 + ... + 357179.
It is an arithmetic number, because the mean of its divisors is an integer number (7979833290).
Almost surely, 253196269135 is an apocalyptic number.
53196269135 is a deficient number, since it is larger than the sum of its proper divisors (10642397185).
53196269135 is a wasteful number, since it uses less digits than its factorization.
53196269135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 523897.
The product of its digits is 1312200, while the sum is 50.
The spelling of 53196269135 in words is "fifty-three billion, one hundred ninety-six million, two hundred sixty-nine thousand, one hundred thirty-five".
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