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532014013541 = 17231360649651
BaseRepresentation
bin1111011110111101000…
…00011001110001100101
31212212012222020002210202
413233132200121301211
532204031041413131
61044223122400245
753302542333653
oct7573640316145
91785188202722
10532014013541
1119569804a72a
1287136500085
133b22685585a
141ba6cd33dd3
15dc8b48bbcb
hex7bde819c65

532014013541 has 8 divisors (see below), whose sum is σ = 587800649664. Its totient is φ = 478948676800.

The previous prime is 532014013523. The next prime is 532014013543. The reversal of 532014013541 is 145310410235.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 532014013541 - 230 = 530940271717 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (532014013543) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 680324435 + ... + 680325216.

It is an arithmetic number, because the mean of its divisors is an integer number (73475081208).

Almost surely, 2532014013541 is an apocalyptic number.

It is an amenable number.

532014013541 is a deficient number, since it is larger than the sum of its proper divisors (55786636123).

532014013541 is a wasteful number, since it uses less digits than its factorization.

532014013541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1360649691.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 532014013541 its reverse (145310410235), we get a palindrome (677324423776).

The spelling of 532014013541 in words is "five hundred thirty-two billion, fourteen million, thirteen thousand, five hundred forty-one".

Divisors: 1 17 23 391 1360649651 23131044067 31294941973 532014013541