Base | Representation |
---|---|
bin | 100110101101011010101… |
… | …1110110011111001110111 |
3 | 200211121101212202020100221 |
4 | 1031122311132303321313 |
5 | 1144131244322443323 |
6 | 15152023411315211 |
7 | 1056241604052166 |
oct | 115326536637167 |
9 | 20747355666327 |
10 | 5320214265463 |
11 | 1771321289679 |
12 | 71b114babb07 |
13 | 2c7903aaaca6 |
14 | 1456dd4273dd |
15 | 935ce87255d |
hex | 4d6b57b3e77 |
5320214265463 has 4 divisors (see below), whose sum is σ = 5320451829240. Its totient is φ = 5319976701688.
The previous prime is 5320214265419. The next prime is 5320214265473. The reversal of 5320214265463 is 3645624120235.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5320214265463 - 221 = 5320212168311 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5320214265473) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 118748293 + ... + 118793086.
It is an arithmetic number, because the mean of its divisors is an integer number (1330112957310).
Almost surely, 25320214265463 is an apocalyptic number.
5320214265463 is a deficient number, since it is larger than the sum of its proper divisors (237563777).
5320214265463 is a wasteful number, since it uses less digits than its factorization.
5320214265463 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 237563776.
The product of its (nonzero) digits is 1036800, while the sum is 43.
Adding to 5320214265463 its reverse (3645624120235), we get a palindrome (8965838385698).
The spelling of 5320214265463 in words is "five trillion, three hundred twenty billion, two hundred fourteen million, two hundred sixty-five thousand, four hundred sixty-three".
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