Base | Representation |
---|---|
bin | 1001111010001110… |
… | …00101000010011011 |
3 | 111201202221211210221 |
4 | 10331013011002123 |
5 | 41343434424430 |
6 | 2235531020511 |
7 | 245561143501 |
oct | 47507050233 |
9 | 14652854727 |
10 | 5320233115 |
11 | 229015097a |
12 | 104589a737 |
13 | 66a2c1c42 |
14 | 386820671 |
15 | 21211057a |
hex | 13d1c509b |
5320233115 has 4 divisors (see below), whose sum is σ = 6384279744. Its totient is φ = 4256186488.
The previous prime is 5320233097. The next prime is 5320233119. The reversal of 5320233115 is 5113320235.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 5113320235 = 5 ⋅1022664047.
It is a cyclic number.
It is not a de Polignac number, because 5320233115 - 27 = 5320232987 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 5320233115.
It is not an unprimeable number, because it can be changed into a prime (5320233119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 532023307 + ... + 532023316.
It is an arithmetic number, because the mean of its divisors is an integer number (1596069936).
Almost surely, 25320233115 is an apocalyptic number.
5320233115 is a deficient number, since it is larger than the sum of its proper divisors (1064046629).
5320233115 is a wasteful number, since it uses less digits than its factorization.
5320233115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1064046628.
The product of its (nonzero) digits is 2700, while the sum is 25.
The square root of 5320233115 is about 72939.9281258215. The cubic root of 5320233115 is about 1745.7292447681.
The spelling of 5320233115 in words is "five billion, three hundred twenty million, two hundred thirty-three thousand, one hundred fifteen".
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