Base | Representation |
---|---|
bin | 11000001100011011000101… |
… | …00111111001101000101111 |
3 | 20222101012022102201221021112 |
4 | 30012031202213321220233 |
5 | 23433141043104204130 |
6 | 305053151120022235 |
7 | 14130551131533113 |
oct | 1406154247715057 |
9 | 228335272657245 |
10 | 53203414522415 |
11 | 15a52494540213 |
12 | 5b73217a6197b |
13 | 238c0a2ab0cc1 |
14 | d1d0b7c8d743 |
15 | 623e2249d495 |
hex | 3063629f9a2f |
53203414522415 has 4 divisors (see below), whose sum is σ = 63844097426904. Its totient is φ = 42562731617928.
The previous prime is 53203414522397. The next prime is 53203414522451. The reversal of 53203414522415 is 51422541430235.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53203414522415 - 26 = 53203414522351 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5320341452237 + ... + 5320341452246.
It is an arithmetic number, because the mean of its divisors is an integer number (15961024356726).
Almost surely, 253203414522415 is an apocalyptic number.
53203414522415 is a deficient number, since it is larger than the sum of its proper divisors (10640682904489).
53203414522415 is a wasteful number, since it uses less digits than its factorization.
53203414522415 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10640682904488.
The product of its (nonzero) digits is 576000, while the sum is 41.
The spelling of 53203414522415 in words is "fifty-three trillion, two hundred three billion, four hundred fourteen million, five hundred twenty-two thousand, four hundred fifteen".
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