Base | Representation |
---|---|
bin | 100110101101100011100… |
… | …1111010101111010001111 |
3 | 200211122011122100220011211 |
4 | 1031123013033111322033 |
5 | 1144132402110402320 |
6 | 15152113133155251 |
7 | 1056252152341033 |
oct | 115330717257217 |
9 | 20748148326154 |
10 | 5320512200335 |
11 | 1771464482542 |
12 | 71b19892bb27 |
13 | 2c7950734b07 |
14 | 14572ac201c3 |
15 | 935eaac455a |
hex | 4d6c73d5e8f |
5320512200335 has 8 divisors (see below), whose sum is σ = 6384651048000. Its totient is φ = 4256385488544.
The previous prime is 5320512200329. The next prime is 5320512200357. The reversal of 5320512200335 is 5330022150235.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5320512200335 - 25 = 5320512200303 is a prime.
It is a super-2 number, since 2×53205122003352 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5320512200297 and 5320512200306.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2039847 + ... + 3847336.
It is an arithmetic number, because the mean of its divisors is an integer number (798081381000).
Almost surely, 25320512200335 is an apocalyptic number.
5320512200335 is a deficient number, since it is larger than the sum of its proper divisors (1064138847665).
5320512200335 is a wasteful number, since it uses less digits than its factorization.
5320512200335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6067937.
The product of its (nonzero) digits is 27000, while the sum is 31.
The spelling of 5320512200335 in words is "five trillion, three hundred twenty billion, five hundred twelve million, two hundred thousand, three hundred thirty-five".
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