Base | Representation |
---|---|
bin | 100110101101100100110… |
… | …1110110101111010001101 |
3 | 200211122021120001011102011 |
4 | 1031123021232311322031 |
5 | 1144132443311343201 |
6 | 15152121225301221 |
7 | 1056253200623563 |
oct | 115331156657215 |
9 | 20748246034364 |
10 | 5320554012301 |
11 | 1771486040490 |
12 | 71b1aa934811 |
13 | 2c79592b4318 |
14 | 1457325c5a33 |
15 | 935ee5d3151 |
hex | 4d6c9bb5e8d |
5320554012301 has 8 divisors (see below), whose sum is σ = 5805331212384. Its totient is φ = 4835958557520.
The previous prime is 5320554012289. The next prime is 5320554012343. The reversal of 5320554012301 is 1032104550235.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5320554012301 - 25 = 5320554012269 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5320554012901) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 45375106 + ... + 45492211.
It is an arithmetic number, because the mean of its divisors is an integer number (725666401548).
Almost surely, 25320554012301 is an apocalyptic number.
It is an amenable number.
5320554012301 is a deficient number, since it is larger than the sum of its proper divisors (484777200083).
5320554012301 is a wasteful number, since it uses less digits than its factorization.
5320554012301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 90872651.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 5320554012301 its reverse (1032104550235), we get a palindrome (6352658562536).
The spelling of 5320554012301 in words is "five trillion, three hundred twenty billion, five hundred fifty-four million, twelve thousand, three hundred one".
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