Base | Representation |
---|---|
bin | 110001100011100101… |
… | …010011110100011001 |
3 | 12002100022121221211101 |
4 | 301203211103310121 |
5 | 1332433321114231 |
6 | 40240002031401 |
7 | 3562413235360 |
oct | 614345236431 |
9 | 162308557741 |
10 | 53210332441 |
11 | 20625933362 |
12 | a390048561 |
13 | 502cbb8516 |
14 | 280ac487d7 |
15 | 15b6634661 |
hex | c63953d19 |
53210332441 has 16 divisors (see below), whose sum is σ = 62470582144. Its totient is φ = 44365377024.
The previous prime is 53210332429. The next prime is 53210332457. The reversal of 53210332441 is 14423301235.
It is a happy number.
53210332441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 53210332441 - 27 = 53210332313 is a prime.
It is a super-4 number, since 4×532103324414 (a number of 44 digits) contains 4444 as substring.
It is not an unprimeable number, because it can be changed into a prime (53210332471) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1146106 + ... + 1191628.
It is an arithmetic number, because the mean of its divisors is an integer number (3904411384).
Almost surely, 253210332441 is an apocalyptic number.
It is an amenable number.
53210332441 is a deficient number, since it is larger than the sum of its proper divisors (9260249703).
53210332441 is a wasteful number, since it uses less digits than its factorization.
53210332441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50080.
The product of its (nonzero) digits is 8640, while the sum is 28.
Adding to 53210332441 its reverse (14423301235), we get a palindrome (67633633676).
The spelling of 53210332441 in words is "fifty-three billion, two hundred ten million, three hundred thirty-two thousand, four hundred forty-one".
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