Base | Representation |
---|---|
bin | 100110101110011111010… |
… | …1000111100010110100111 |
3 | 200211211100020201222122211 |
4 | 1031130332220330112213 |
5 | 1144201002420300403 |
6 | 15153044012504251 |
7 | 1056352615300426 |
oct | 115347650742647 |
9 | 20754306658584 |
10 | 5322515400103 |
11 | 17722a2205140 |
12 | 71b65777b087 |
13 | 2c7bac75c715 |
14 | 14587acad2bd |
15 | 936b68ba06d |
hex | 4d73ea3c5a7 |
5322515400103 has 8 divisors (see below), whose sum is σ = 5947999472016. Its totient is φ = 4720634500800.
The previous prime is 5322515400029. The next prime is 5322515400149. The reversal of 5322515400103 is 3010045152235.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5322515400103 - 217 = 5322515269031 is a prime.
It is a super-3 number, since 3×53225154001033 (a number of 39 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5322515401103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5900792676 + ... + 5900793577.
It is an arithmetic number, because the mean of its divisors is an integer number (743499934002).
Almost surely, 25322515400103 is an apocalyptic number.
5322515400103 is a deficient number, since it is larger than the sum of its proper divisors (625484071913).
5322515400103 is a wasteful number, since it uses less digits than its factorization.
5322515400103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11801586305.
The product of its (nonzero) digits is 18000, while the sum is 31.
The spelling of 5322515400103 in words is "five trillion, three hundred twenty-two billion, five hundred fifteen million, four hundred thousand, one hundred three".
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