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53230124335 = 5313131097189
BaseRepresentation
bin110001100100110000…
…110011110100101111
312002101200212111012111
4301210300303310233
51333003402434320
640241550144451
73563043406603
oct614460636457
9162350774174
1053230124335
11206360212a3
12a3967b2127
135034027cbb
14280d71b503
1515b8243a5a
hexc64c33d2f

53230124335 has 16 divisors (see below), whose sum is σ = 66147390720. Its totient is φ = 41078718720.

The previous prime is 53230124309. The next prime is 53230124347. The reversal of 53230124335 is 53342103235.

It is not a de Polignac number, because 53230124335 - 25 = 53230124303 is a prime.

It is a super-2 number, since 2×532301243352 (a number of 22 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (31).

It is a junction number, because it is equal to n+sod(n) for n = 53230124297 and 53230124306.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 500080 + ... + 597109.

It is an arithmetic number, because the mean of its divisors is an integer number (4134211920).

Almost surely, 253230124335 is an apocalyptic number.

53230124335 is a deficient number, since it is larger than the sum of its proper divisors (12917266385).

53230124335 is a wasteful number, since it uses less digits than its factorization.

53230124335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1097538.

The product of its (nonzero) digits is 32400, while the sum is 31.

The spelling of 53230124335 in words is "fifty-three billion, two hundred thirty million, one hundred twenty-four thousand, three hundred thirty-five".

Divisors: 1 5 31 155 313 1565 9703 48515 1097189 5485945 34012859 170064295 343420157 1717100785 10646024867 53230124335