Base | Representation |
---|---|
bin | 100110101110101110011… |
… | …0011110000001100001001 |
3 | 200211212122112011002021002 |
4 | 1031131130303300030021 |
5 | 1144203022004102340 |
6 | 15153210133224345 |
7 | 1056401302431212 |
oct | 115353463601411 |
9 | 20755575132232 |
10 | 5323021550345 |
11 | 1772531992324 |
12 | 71b7791920b5 |
13 | 2c7c60588cc5 |
14 | 1458c81c6409 |
15 | 936e604a715 |
hex | 4d75ccf0309 |
5323021550345 has 4 divisors (see below), whose sum is σ = 6387625860420. Its totient is φ = 4258417240272.
The previous prime is 5323021550333. The next prime is 5323021550417. The reversal of 5323021550345 is 5430551203235.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 3419866106944 + 1903155443401 = 1849288^2 + 1379549^2 .
It is a cyclic number.
It is not a de Polignac number, because 5323021550345 - 214 = 5323021533961 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5323021550299 and 5323021550308.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 532302155030 + ... + 532302155039.
It is an arithmetic number, because the mean of its divisors is an integer number (1596906465105).
Almost surely, 25323021550345 is an apocalyptic number.
It is an amenable number.
5323021550345 is a deficient number, since it is larger than the sum of its proper divisors (1064604310075).
5323021550345 is a wasteful number, since it uses less digits than its factorization.
5323021550345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1064604310074.
The product of its (nonzero) digits is 270000, while the sum is 38.
The spelling of 5323021550345 in words is "five trillion, three hundred twenty-three billion, twenty-one million, five hundred fifty thousand, three hundred forty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •