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5323021550345 = 51064604310069
BaseRepresentation
bin100110101110101110011…
…0011110000001100001001
3200211212122112011002021002
41031131130303300030021
51144203022004102340
615153210133224345
71056401302431212
oct115353463601411
920755575132232
105323021550345
111772531992324
1271b7791920b5
132c7c60588cc5
141458c81c6409
15936e604a715
hex4d75ccf0309

5323021550345 has 4 divisors (see below), whose sum is σ = 6387625860420. Its totient is φ = 4258417240272.

The previous prime is 5323021550333. The next prime is 5323021550417. The reversal of 5323021550345 is 5430551203235.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3419866106944 + 1903155443401 = 1849288^2 + 1379549^2 .

It is a cyclic number.

It is not a de Polignac number, because 5323021550345 - 214 = 5323021533961 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5323021550299 and 5323021550308.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 532302155030 + ... + 532302155039.

It is an arithmetic number, because the mean of its divisors is an integer number (1596906465105).

Almost surely, 25323021550345 is an apocalyptic number.

It is an amenable number.

5323021550345 is a deficient number, since it is larger than the sum of its proper divisors (1064604310075).

5323021550345 is a wasteful number, since it uses less digits than its factorization.

5323021550345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1064604310074.

The product of its (nonzero) digits is 270000, while the sum is 38.

The spelling of 5323021550345 in words is "five trillion, three hundred twenty-three billion, twenty-one million, five hundred fifty thousand, three hundred forty-five".

Divisors: 1 5 1064604310069 5323021550345