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5323100364403 = 10361351374831
BaseRepresentation
bin100110101110110000110…
…0000011001111001110011
3200211212212000110020211021
41031131201200121321303
51144203202143130103
615153222030400311
71056403250354623
oct115354140317163
920755760406737
105323100364403
111772572423508
1271b79b660097
132c7c739c2643
141458d4860883
15936ece17bbd
hex4d761819e73

5323100364403 has 4 divisors (see below), whose sum is σ = 5323151842848. Its totient is φ = 5323048885960.

The previous prime is 5323100364397. The next prime is 5323100364431. The reversal of 5323100364403 is 3044630013235.

5323100364403 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5323100364403 - 221 = 5323098267251 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5323100664403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25583803 + ... + 25791028.

It is an arithmetic number, because the mean of its divisors is an integer number (1330787960712).

Almost surely, 25323100364403 is an apocalyptic number.

5323100364403 is a deficient number, since it is larger than the sum of its proper divisors (51478445).

5323100364403 is a wasteful number, since it uses less digits than its factorization.

5323100364403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51478444.

The product of its (nonzero) digits is 77760, while the sum is 34.

Adding to 5323100364403 its reverse (3044630013235), we get a palindrome (8367730377638).

The spelling of 5323100364403 in words is "five trillion, three hundred twenty-three billion, one hundred million, three hundred sixty-four thousand, four hundred three".

Divisors: 1 103613 51374831 5323100364403